Homework 4 - Function Overloading and by-reference Parameters

Since Midterm 2 is Monday October 24th, no late assignments will be accepted beyond 5:00pm on Friday October 21st, so that the solutions can be posted to be studied before the midterm.

Name your files hw4_<problem>.cpp, such as hw4_1.cpp. Email all the cpp files to my account.

1. (10 points) This purpose of this problem is to work with function overloading. You will write several versions of functions called find_min(), get_input() and print_min(). print_min() and get_input() will be void functions. find_min() will return a value. The functions are as follows:
   • The first version of print_min() will take one integer argument and print the message "The minimum is <value>.\n", where <value> is the contents of the integer argument.
   • The second version of print_min() will take one double argument and print the message "The minimum is <value>.\n" with 4 decimal places of precision for <value>.
   • The first version of find_min() will take two integer arguments and it will return the minimum of the two integers.
   • The second version of find_min() will take two double arguments and it will return the minimum of the two doubles.
   • The third version of find_min() will take three integer arguments and it will return the minimum of the three integers.
   • The first version of get_input() has two by-reference integer arguments. It will prompt the user for two integers and read them into the by-reference parameters.
   • The second version of get_input() has two by-reference double arguments. It will prompt the user for two doubles and read them into the by-reference parameters.
   • The third version of get_input() has three by-reference integer arguments. It will prompt the user for three integers and read them into the by-reference parameters.
   Use the following main function for this problem:

   int main()
   {
     int num1, num2, num3;
     double dnum1, dnum2;
   
     // Two integer version
     get_input(num1, num2);
     print_min(find_min(num1, num2));
   
     // Two double version
     get_input(dnum1, dnum2);
     print_min(find_min(dnum1, dnum2));
   
     // Three integer version
     get_input(num1, num2, num3);
     print_min(find_min(num1, num2, num3));
   
     return 0;
   }
   

2. (10 points) Modify your simple menu program from Homework 3. The menu options will remain the same, but now each option will use a function calls instead of having all the option statements within the switch() statement.

     Welcome to the CS221 Homework 4 Menu
     ====================================
     1.  Multiply two integers
     2.  Divide two integers
     3.  Check if a number is within the range 10-20
     4.  Find the minimum of a list of 3 numbers
   
     0.  Exit
     ====================================
     Enter selection:
   

   From within each case statement, there will be a void function that gets the input from the user using by-reference parameters and a second void function that takes the input as by-value parameters, does the task and prints the result to the screen. For example, the first menu item case statement would be:

     case 1:
       get_input(a, b);
       cout << "The result is " << multiply(a, b) << endl;
       break;
   

   You should have at least the following 7 functions in your final code. More functions are fine if you wish to break each menu item task into subtasks.
   • 3 versions of get_input(). One version will have one by-reference integer argument, the second version will have two by-reference integer arguments and the third will have three by-reference integer arguments. Each will prompt the user for the required number of integers and read in to the by-reference parameters. This is similiar to Problem 1.
   • int multiply(int a, int b) will multiply the integers and return the result.
   • double division(int a, int b) will divide the integers and return the result.
   • bool do_check(int a) will check if the integer is in range. If it is in range, it will return true. Otherwise, it will return false. You will need an if statement in main() to check the return value and print the appropriate message.
   • int find_minimum(int a, int b, int c) will find the minimum and return it (similiar to Problem 1).